Proton speed needed to circle the earth

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SUMMARY

The discussion focuses on calculating the speed required for a proton to orbit the Earth at an altitude of 1550.0 km above the magnetic equator, given Earth's magnetic field intensity of 4.19 × 10-8 T. The relevant equation used is r = m*v/Q*B, where r is the radius of the orbit, m is the mass of the proton, v is the velocity, Q is the charge of the proton, and B is the magnetic field strength. Participants confirm that the approach to solving for velocity is correct, emphasizing the importance of using accurate values for mass and charge in the calculations.

PREREQUISITES
  • Understanding of circular motion in magnetic fields
  • Familiarity with the equation r = m*v/Q*B
  • Knowledge of the mass and charge of a proton
  • Basic principles of electromagnetism
NEXT STEPS
  • Calculate the radius of the orbit using Earth's radius and the given altitude
  • Determine the mass and charge of a proton for accurate calculations
  • Explore the effects of varying magnetic field strengths on proton motion
  • Investigate practical applications of protons in magnetic fields, such as in particle accelerators
USEFUL FOR

Students in physics, educators teaching electromagnetism, and researchers interested in particle motion in magnetic fields.

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Homework Statement



Assume that Earth’s magnetic field is every-
where perpendicular to the path of a proton
and that Earth’s magnetic field has an inten-
sity of 4.19 × 10−8 T.
What speed would a proton need to achieve
in order to circle Earth 1550.0 km above the
magnetic equator?
Answer in units of m/s.



Homework Equations



r=m*v/Q*B
r=(r Earth + r given in the question )

The Attempt at a Solution



i solved for v but I am not sure if what I am doing is correct
 
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You are in right track.
 
thanX
 

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