Prove a=a^+-a^- & |a|=a^++a^- for Easy Analysis Proof Homework

  • Thread starter Thread starter iamalexalright
  • Start date Start date
  • Tags Tags
    Analysis Proof
Click For Summary

Homework Help Overview

The discussion revolves around proving two identities involving the positive and negative parts of a real number, defined as a^{+} = (|a| + a) / 2 and a^{-} = (|a| - a) / 2. Participants are tasked with demonstrating that a = a^{+} - a^{-} and |a| = a^{+} + a^{-}.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definitions of a^{+} and a^{-} and attempt to manipulate these expressions to prove the identities. Some express uncertainty about the complexity of their proofs, while others suggest starting from the definitions to derive the results.

Discussion Status

There is ongoing exploration of the proofs, with some participants providing partial derivations and questioning the necessity of certain steps. Guidance has been offered regarding the structure of proofs and the importance of clarity in writing.

Contextual Notes

Participants mention their inexperience with proof writing and seek advice on how to present their work clearly, particularly in using LaTeX for formatting.

iamalexalright
Messages
157
Reaction score
0

Homework Statement


The positive part of an a in R is defined by:

[tex]a^{+} = (|a| + a) / 2[/tex]

and the negative by:

[tex]a^{-} = (|a| - a) / 2[/tex].

Prove that [tex]a = a^{+} - a^{-}[/tex] and [tex]|a| = a^{+} + a^{-}[/tex]

Homework Equations


The field axioms(closure, associativity,...)
The order axioms
Definition of the absolute value (and a few theorems)



The Attempt at a Solution



Now, I'm new at proof writing, but this seems too simple (and I don't know if providing all these steps is too much or not?) : /

[tex]a = a^{+} - a^{-} <br /> = (|a| + a)/2 - (|a| - a)/2 <br /> = 2^{-1}(|a| + a) - 2^{-1}(|a| - a) <br /> = 2^{-1}(|a| + a - |a| + a) <br /> = 2^{-1}(2a)<br /> = a[/tex]


(btw, how can I separate my proof line by line with LaTeX?)
 
Physics news on Phys.org
It looks like you have proved that a = a, which is obvious to the most casual observer, and for this reason, not very interesting.

For the first part, start with a+ - a- and use your definitions. What do you get?
For the second part, start with a+ + a-. What do you get this time?

For your last questions, use separate LaTeX lines.
 
alright, so we'd have something like this:

if [tex]a \geq 0[/tex] then [tex]|a| = a[/tex]
[tex](|a| + a) / 2 - (|a| - a) / 2 =[/tex]
[tex]= (a + a) / 2 - (a - a) / 2 =[/tex]
[tex]= 2(a)/2 - (0)/2 =[/tex]
[tex]= a[/tex]

if [tex]a < 0[/tex] then[tex]|a| = -a[/tex]
and then the same procedure
 
iamalexalright said:
alright, so we'd have something like this:

if [tex]a \geq 0[/tex] then [tex]|a| = a[/tex]
[tex](|a| + a) / 2 - (|a| - a) / 2 =[/tex]
[tex]= (a + a) / 2 - (a - a) / 2 =[/tex]
[tex]= 2(a)/2 - (0)/2 =[/tex]
[tex]= a[/tex]

if [tex]a < 0[/tex] then[tex]|a| = -a[/tex]
and then the same procedure

This is correct, but is more complicated than it needs to be.

a+ - a-
= (1/2)(|a| + a) - (1/2)(|a| - a)
= (1/2)[|a| - |a| + a -(-a)]
= (1/2)(2a) = a
This is true for any real value of a, not just for a >= 0.

You should be able to do something similar for the other part.
 
Alright, thanks Mark44. I included it just because I'm not used to writing proofs yet (ie I don't exactly know what to include/omit yet).
 
Include everything that needs to be there, and omit all the rest. Start at one side of the equation you are trying to prove. Use definitions to rewrite the expression on that side and work toward making what you start with look like the other side you're trying to get to.
 

Similar threads

Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 14 ·
Replies
14
Views
5K