Albert1
- 1,221
- 0
A trapezoid ABCD ,AB//CD ,AD=BC
Prove :
$AC^2=AD^2+(AB).(CD)$
Prove :
$AC^2=AD^2+(AB).(CD)$
The discussion centers on proving the geometric identity for trapezoid ABCD, where AB is parallel to CD and AD equals BC. The formula to be proven is \(AC^2 = AD^2 + (AB) \cdot (CD)\). Participants emphasize the importance of understanding trapezoidal properties and the Pythagorean theorem in establishing this relationship. The proof relies on the congruence of triangles formed within the trapezoid.
PREREQUISITESStudents of geometry, mathematics educators, and anyone interested in mastering geometric proofs and properties of trapezoids.
Albert said:A trapezoid ABCD ,AB//CD ,AD=BC
Prove :
$AC^2=AD^2+(AB).(CD)$