- #1
roam
- 1,271
- 12
Prove by definition the statement
lim x->4 √x = 2
This is what I've done:
Given ε>0
|(√x)-2| = |√x-2|< ε if |x-4|< ε^2
I choose δ = ε^2
0<|x-4|< ε^2
=> |x-2|< √ε^2 = ε
Hence lim x->4 √x = 2
So, what do you think? Did I do the process correctly?
lim x->4 √x = 2
This is what I've done:
Given ε>0
|(√x)-2| = |√x-2|< ε if |x-4|< ε^2
I choose δ = ε^2
0<|x-4|< ε^2
=> |x-2|< √ε^2 = ε
Hence lim x->4 √x = 2
So, what do you think? Did I do the process correctly?
Last edited: