Prove DF² = AF·EF and BF = DF for tangent lines to a circle

[Anzas]

AD and BD touch the circule at points A and B
AC is parallel to BD
prove that:

1. DF^2 = AF*EF
2. BF = DF

its obvious that BF^2 = EF * AF i tried proving that DF = FB but with no luck.

edit: i uploaded the wrong picture earlier, terribly sorry i have so many of them

 

[Anzas]

anyone?

 

[bross7]

I cannot see the image so I cannot help you out. If you are still stuck a faster way may be to send the image in an email and I could help you out then.

 

[TenaliRaman]

The attachment if you see is yet to be approved ...

-- AI

 

[Anzas]

never mind guys i managed to solve it, thanks anyway