Prove direct product of G1 x G2 is abelian

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SUMMARY

The direct product of two abelian groups, G1 and G2, is also abelian. Given elements a1 and a2 from G1 and b1 and b2 from G2, the multiplication of elements in the direct product G1 x G2 can be expressed as (a1, b1)(a2, b2) = (a1a2, b1b2). Since both G1 and G2 are abelian, it follows that a1a2 = a2a1 and b1b2 = b2b1, confirming that G1 x G2 is abelian.

PREREQUISITES
  • Understanding of group theory concepts, specifically abelian groups.
  • Familiarity with direct products of groups.
  • Basic knowledge of group operations and properties.
  • Ability to manipulate ordered pairs in mathematical expressions.
NEXT STEPS
  • Study the properties of abelian groups in detail.
  • Explore examples of direct products of finite groups.
  • Learn about homomorphisms and isomorphisms in group theory.
  • Investigate the implications of non-abelian groups and their direct products.
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Students of abstract algebra, mathematicians interested in group theory, and educators teaching concepts related to group structures and properties.

kathrynag
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Homework Statement



Prove that if G1 and G2 are abelian, then the direct product G1 x G2 is abelian.


Homework Equations





The Attempt at a Solution


let G1 and G2 be abelian. Then for a1,a2,b1,b2, we have a1b1=b1a1 and a2b2=b2a2.
The direct product is the set of all ordered pairs (x1,x2) such that x1 is in G1 and x2 is in G2.
Let x1 be in G1 and x2 be in G2.
Then G1 x G= (x1, x2)
I'm not quite sure how to show this is abelian.
 
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Take two elements in G1 x G2. What does these elements look like? What happens if you multiply them?
 
Let a be in G1 b in G2. Then ab=ba
 
No, I take an element in G_1 x G_2. What does this look like?
 
oh, so we have (a, b) and (c,d)
We have (a,b)(c,d)=(ac,bd)
But ac=ca and bd=db
So (ac,bd)=(ca,db)=(c,d)(a,b)
 
Yes! good job!
 
That's really all I have to do? it seems so simple.
 
Yes, it's that simple :smile:
 

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