Prove Evenness of Poisson Kernel for Fixed $r$

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SUMMARY

For a fixed value of $r$ where $0 \leq r < 1$, the Poisson kernel $P(r,\theta)$ is proven to be an even function. By substituting $-r$ into the Poisson kernel formula, it is shown that $P(-r,\theta)$ simplifies to the same expression as $P(r,\theta)$, confirming its evenness. The key mathematical manipulation involves recognizing that the cosine function, $\cos \theta$, is even, which reinforces the conclusion that the Poisson kernel maintains its even property with respect to $\theta$.

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For a fixed $r$ with $0\leq r < 1$, prove that $P(r,\theta)$ is an even function.Take $-r$.
Then
\begin{alignat*}{3}
P(-r,\theta) & = & \frac{1}{2\pi}\frac{1 - (-r)^2}{1 - 2(-r)\cos\theta + (-r)^2}\\
& = & \frac{1}{2\pi}\frac{1 - r^2}{1 + 2r\cos\theta + r^2}
\end{alignat*}
I have $1 + 2r\cos\theta - r^2$. How can I get back the original denominator?
 
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dwsmith said:
For a fixed $r$ with $0\leq r < 1$, prove that $P(r,\theta)$ is an even function.

Because r is fixed the only variable remains $\theta$ and $cos \theta$ is an even function of $\theta$...

Kind regards

$\chi$ $\sigma$
 

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