Scherie Messages 3 Reaction score 0 Thread starter Jan 14, 2016 #1 Let E be an extension of F and let a, b belong to E. Prove that F(a,b) =F(a)(b) = F(b)(a).
Deveno Science Advisor Gold Member MHB Messages 2,726 Reaction score 6 Jan 14, 2016 #2 May we assume that $a$ and $b$ are algebraic over $F$?
Scherie Messages 3 Reaction score 0 Jan 14, 2016 #3 Deveno said: May we assume that $a$ and $b$ are algebraic over $F$? Yes
Deveno Science Advisor Gold Member MHB Messages 2,726 Reaction score 6 Jan 14, 2016 #4 Pick a basis $\{u_j\}$ for $F(a)$ over $F$, and a basis $\{v_k\}$ for $F(b)$ over $F$. Consider the set: $\{u_jv_k\}$, and use a dimensional argument.
Pick a basis $\{u_j\}$ for $F(a)$ over $F$, and a basis $\{v_k\}$ for $F(b)$ over $F$. Consider the set: $\{u_jv_k\}$, and use a dimensional argument.