- #1

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## Main Question or Discussion Point

can somebody prove that for all a,b,c>0:

a/(b+c) + b/(a+c) + c/(a+b) >= 3/2

a/(b+c) + b/(a+c) + c/(a+b) >= 3/2

- Thread starter barbiemathgurl
- Start date

- #1

- 12

- 0

can somebody prove that for all a,b,c>0:

a/(b+c) + b/(a+c) + c/(a+b) >= 3/2

a/(b+c) + b/(a+c) + c/(a+b) >= 3/2

- #2

morphism

Science Advisor

Homework Helper

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Here's a hint: Set x=b+c, y=a+c, and z=a+b. Then re-write the left side as: 1/2 [(x/y + y/x) + (y/z + z/y) + (z/x + x/z) - 3].

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