can somebody prove that for all a,b,c>0:
a/(b+c) + b/(a+c) + c/(a+b) >= 3/2
There are probably a few ways you can do this.
Here's a hint: Set x=b+c, y=a+c, and z=a+b. Then re-write the left side as: 1/2 [(x/y + y/x) + (y/z + z/y) + (z/x + x/z) - 3].
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