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Prove for all a,b,c>0: a/(b+c) + b/(a+c) + c/(a+b) >= 3/2 ?

  1. Jul 8, 2007 #1
    can somebody prove that for all a,b,c>0:

    a/(b+c) + b/(a+c) + c/(a+b) >= 3/2
     
  2. jcsd
  3. Jul 8, 2007 #2

    morphism

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    There are probably a few ways you can do this.

    Here's a hint: Set x=b+c, y=a+c, and z=a+b. Then re-write the left side as: 1/2 [(x/y + y/x) + (y/z + z/y) + (z/x + x/z) - 3].
     
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