Prove identity (sinx+cosx)/(secx+cscx)= sinxcosx

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SUMMARY

The identity \(\frac{\sin(x) + \cos(x)}{\sec(x) + \csc(x)} = \sin(x) \cos(x)\) can be proven by rewriting the left-hand side (LHS) in terms of sine and cosine functions. The LHS simplifies to \(\frac{\sin(x) + \cos(x)}{\frac{1}{\cos(x)} + \frac{1}{\sin(x)}}\). By combining the terms in the denominator, the identity can be verified step by step, leading to the conclusion that both sides are indeed equal.

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prove this identity

(sinx+cosx)/(secx+cscx)= sinxcosx if you could list out the steps it would be appreciated
 
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Hello, and welcome to MHB! (Wave)

Since the RHS is in terms of the sine and cosine functions, the first thing I would do is write the LHS in terms of these functions only:

$$\frac{\sin(x)+\cos(x)}{\dfrac{1}{\cos(x)}+\dfrac{1}{\sin(x)}}$$

Now, combine terms in the denominator...what do you get?
 

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