Prove Inequality: (ab+cd)^2 ≤ (a^2+c^2)(b^2+d^2)

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SUMMARY

The inequality \((ab + cd)^2 \leq (a^2 + c^2)(b^2 + d^2)\) can be proven by manipulating both sides of the equation. The left-hand side (LHS) expands to \((ab)^2 + 2abcd + (cd)^2\), while the right-hand side (RHS) expands to \((ab)^2 + (ad)^2 + (bc)^2 + (cd)^2\). The critical step is to demonstrate that \(2abcd \leq (ad)^2 + (bc)^2\), which can be achieved by recognizing that the expression can be rewritten as \((ad - bc)^2 \geq 0\), thus confirming the inequality holds true.

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Homework Statement



Prove that \left(ab+cd\right)^{2} \leq \left(a^{2}+c^{2}\right)\left(b^{2}+d^{2}\right)


Homework Equations



None

The Attempt at a Solution



I've broken the LHS down to the following:

\left(ab\right)^{2}+2abcd+\left(cd\right)^{2}

The RHS:

\left(ab\right)^{2} + \left(ad\right)^{2} + \left(bc\right)^{2} + \left(cd\right)^{2}

So, ultimately... it works out that I need to show 2abcd \leq \left(ad\right)^{2} + \left(bc\right)^{2}

This is where I'm getting stuck... Any suggestions...
 
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rbzima said:

Homework Statement



Prove that \left(ab+cd\right)^{2} \leq \left(a^{2}+c^{2}\right)\left(b^{2}+d^{2}\right)

Homework Equations



None

The Attempt at a Solution



I've broken the LHS down to the following:

\left(ab\right)^{2}+2abcd+\left(cd\right)^{2}

The RHS:

\left(ab\right)^{2} + \left(ad\right)^{2} + \left(bc\right)^{2} + \left(cd\right)^{2}

So, ultimately... it works out that I need to show 2abcd \leq \left(ad\right)^{2} + \left(bc\right)^{2}

This is where I'm getting stuck... Any suggestions...

Yup, so far so good, now subtract 2abcd from both sides, and you'll get:

(ad) ^ 2 - 2(ad)(bc) + (bc) ^ 2 \geq 0

Does the LHS of this inequality remind you of something?
 
VietDao29 said:
Yup, so far so good, now subtract 2abcd from both sides, and you'll get:

(ad) ^ 2 - 2(ad)(bc) + (bc) ^ 2 \geq 0

Does the LHS of this inequality remind you of something?


Wow, long night...
http://scienceblogs.com/insolence/facepalm.jpg​
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Last edited by a moderator:
Just use (A-B)2=A2-2AB+B2.

Regards.
 
rbzima said:

Homework Statement



Prove that \left(ab+cd\right)^{2} \leq \left(a^{2}+c^{2}\right)\left(b^{2}+d^{2}\right)


Homework Equations



None

The Attempt at a Solution



I've broken the LHS down to the following:

\left(ab\right)^{2}+2abcd+\left(cd\right)^{2}

The RHS:

\left(ab\right)^{2} + \left(ad\right)^{2} + \left(bc\right)^{2} + \left(cd\right)^{2}

So, ultimately... it works out that I need to show 2abcd \leq \left(ad\right)^{2} + \left(bc\right)^{2}

This is where I'm getting stuck... Any suggestions...


Refer to Cauchy–Schwarz inequality for more information (=
 

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