Prove \mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+} is Countable

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Homework Help Overview

The discussion revolves around proving that the Cartesian product \(\mathbb{Z}^{+} \times \mathbb{Z}^{+} \times \mathbb{Z}^{+}\) is countable. Participants are exploring the properties of countable sets and the relationships between them.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants express confusion about how to begin the proof. Others suggest demonstrating a bijection between \(\mathbb{N}\) and \(\mathbb{Z} \times \mathbb{Z}\) as a potential approach, and then extending that to \(\mathbb{Z} \times \mathbb{Z} \times \mathbb{Z}\).

Discussion Status

There are various lines of reasoning being explored, with some participants indicating they have made progress by establishing bijections. However, there is no explicit consensus on a complete method for the proof yet.

Contextual Notes

Participants note the challenge of transitioning from previous coursework, highlighting the difficulty of the current material in relation to their prior knowledge.

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Homework Statement


Prove that [tex]\mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+}[/tex] is countable, where X is the Cartesian product.

Homework Equations


The Attempt at a Solution


I'm lost as to where to start proving this.
 
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The Captain said:

Homework Statement


Prove that [tex]\mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+}[/tex] is countable, where X is the Cartesian product.


Homework Equations





The Attempt at a Solution


I'm lost as to where to start proving this.

do you know how to prove this

[tex]\mathbb Z^{+} X \: \mathbb Z^{+}[/tex]

is countable?
 
There are many ways to do this you show that there it bijection from N to ZxZ ,that is , ZxZ is countable. Then show that there is bijection from ZxZ to ZxZxZ.

EDIT
someone beat me to it.
 
I had to prove that [tex]\mathbb Z^{+} \: X \: Z^{+} \: \rightarrow \: Z^{+}[/tex] was one-one and onto using [tex]f(a,b)=2^{a-1}(2b-1)[/tex], does that count for proving it's countable, and if it's not, no I don't know how to prove it's countable.

The class I'm taking is a giant leap from Calc 4, and Abstract Algebra isn't even pre-req though it probably should be because the professor keeps asking who's taking it before.
 
Yes, that is a bijection. So you have already shown the first part all you need to do provide a bijection from ZxZxZ to ZxZ .
 

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