Prove: p - q Divides p - 1 Implies q - p Divides q - 1

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Homework Help Overview

The discussion revolves around a number theory problem involving integers p and q, specifically proving a divisibility condition. The original poster presents a scenario where p is less than q and explores the implications of the divisibility of p - q with respect to p - 1.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss how to relate the conclusion of the problem to the initial hypothesis, considering algebraic manipulations involving the terms p - 1 and q - 1. There are suggestions to rewrite expressions and rearrange equations to explore the relationships between the variables.

Discussion Status

The discussion is ongoing, with participants actively engaging in algebraic manipulation and exploring different approaches to connect the given conditions. There is no explicit consensus yet, but various lines of reasoning are being examined.

Contextual Notes

Participants are working under the assumption that p and q are positive integers, and the specific conditions of the problem are guiding their exploration of divisibility relationships.

Dustinsfl
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Let p,q ∈ ℤ+ , p < q. Prove that if p - q divides p - 1, then q - p divides q - 1.

So if p - q divides p - 1, then k*(p - q) = p - 1.

Now what?
 
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Now you should relate the conclusion you want to the hypothesis. How can you rewrite q -1 to introduce the p - 1 term (and why would this help you).
 


Multiply through by k and then bring over the p from the right side (and simplify that with kp). Then subtract both sides by q and rearrange.
 


By doing that, it only yields k·p - k·q - p = p·(k - 1) - k·q ⇒ p·(k - 1) = k·q - 1. How can that be manipulated to fit the conclusion?
 


What I was thinking was: p·(k - 1) - k·q = -1, then add q to both sides to give q-1 on the right side and simplify -kq + q. Then rearrange the resulting left side of the equation.
 

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