Prove: Tan^2 - sin^2 = sin^4*Sec^4

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SUMMARY

The equation Tan² - sin² = sin⁴ * Sec² was discussed, with initial confusion regarding the manipulation of the left side. The correct approach involves recognizing that Tan² can be expressed as sin²/cos², leading to the simplification of the equation. Ultimately, the problem was clarified, revealing that the correct formulation is Tan² - sin² = sin⁴ * Sec², which was confirmed by the participants.

PREREQUISITES
  • Understanding of trigonometric identities, specifically Tan and Sec functions.
  • Familiarity with algebraic manipulation of fractions and equations.
  • Knowledge of sine and cosine functions and their relationships.
  • Basic skills in simplifying expressions involving trigonometric functions.
NEXT STEPS
  • Study the derivation and properties of trigonometric identities.
  • Practice simplifying complex trigonometric expressions using algebraic techniques.
  • Explore the relationship between sine, cosine, and tangent functions in depth.
  • Learn about the applications of Secant in trigonometric equations.
USEFUL FOR

Students studying trigonometry, educators teaching trigonometric identities, and anyone looking to strengthen their algebraic manipulation skills in relation to trigonometric functions.

Miike012
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Homework Statement


Prove:
Tan^2 - sin^2 = sin^4*Sec^4


This one I am having trouble with... My thought is that I need to make a fraction on the lift side some how ... then cross multiply then some how remove the denominator...?
Can some one please give me a hint.. thank you.

The Attempt at a Solution



Tan^2 - sin^2
.
.
= sin^2/cos^2 - sin^2

=sin^2/cos^2 - sin^4/sin^2
 
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Hi Miike012! :smile:

(try using the X2 icon just above the Reply box :wink:)
Miike012 said:
Tan^2 - sin^2
.
.
= sin^2/cos^2 - sin^2

Instead, try = tan2 - tan2cos2 :smile:
 
I actually wrote down the probl. wrong...
It is

Tan^2 - sin^2 = sin^4*Sec^2
I figured it out though.
 

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