Prove that 5^(2/3) is irrational

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The discussion centers on proving that 5^(2/3) is irrational. Participants attempted various proof strategies, including assuming 5^(2/3) is rational and manipulating it into a form involving integers a and b. A suggestion was made to simplify the proof by expressing 5^(2/3) as the cube root of 25, which may provide a clearer path to the conclusion. Ultimately, the consensus is that 5^(2/3) cannot be expressed as a fraction of integers, confirming its irrationality.

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Homework Statement


Prove that 5^(2/3) is irrational

Homework Equations





The Attempt at a Solution



I tried writing a proof but that is not getting me any where.

This is what I did so far -

Show that 52/3 is irrational

Proof: Suppose that 52/3 is rational:
52/3 = a/b
52/33/2 = a3/2/b3/2
5(b3/2) = a3/2
Substitute a = 2n + 1, b = 2m + 1;

I don't know if I'm suppose to do like this?
 
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P-Illiterate said:

Homework Statement


Prove that 5^(2/3) is irrational

Homework Equations





The Attempt at a Solution



I tried writing a proof but that is not getting me any where.

This is what I did so far -

Show that 52/3 is irrational

Proof: Suppose that 52/3 is rational:
52/3 = a/b
52/3 3/2 = a3/2/b3/2
5(b3/2) = a3/2
Substitute a = 2n + 1, b = 2m + 1;

I don't know if I'm suppose to do like this?

It might be simpler to use the fact that 52/3 = ##\sqrt[3]{25}##
 
Mark44 said:
It might be simpler to use the fact that 52/3 = ##\sqrt[3]{25}##

:approve:
Gracias
 

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