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Prove that (K)^(-1) = (C degree)^(-1)

  1. Sep 11, 2007 #1
    1. The problem statement, all variables and given/known data
    The lesson is about thermal expansion:
    Prove:
    [tex] K^{-1} = (C^{\circ})^{-1}[/tex]



    2. Relevant equations



    3. The attempt at a solution
    I don't know how to do this problem.... but Celsius degree results from a change in temperature which can be converted to kelvin....
    so C^(degrees) = K
     
  2. jcsd
  3. Sep 11, 2007 #2

    berkeman

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    Staff: Mentor

    If you are talking just about the two temperature scales (Kelvin and Celsius), then there is a simple relation between them, and what you have shown is not it.
     
  4. Sep 12, 2007 #3
    given 10 degrees as the final temp. and 5 degrees as the initial temp.
    both C degrees and K have the formula Tf - Ti;
    1/(K) = 1/(C degrees)
    1/(tf - ti) = 1/(tf - ti)
    1/5 = 1/5
     
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