# Prove that (K)^(-1) = (C degree)^(-1)

1. Sep 11, 2007

### Edwardo_Elric

1. The problem statement, all variables and given/known data
The lesson is about thermal expansion:
Prove:
$$K^{-1} = (C^{\circ})^{-1}$$

2. Relevant equations

3. The attempt at a solution
I don't know how to do this problem.... but Celsius degree results from a change in temperature which can be converted to kelvin....
so C^(degrees) = K

2. Sep 11, 2007

### Staff: Mentor

If you are talking just about the two temperature scales (Kelvin and Celsius), then there is a simple relation between them, and what you have shown is not it.

3. Sep 12, 2007

### Edwardo_Elric

given 10 degrees as the final temp. and 5 degrees as the initial temp.
both C degrees and K have the formula Tf - Ti;
1/(K) = 1/(C degrees)
1/(tf - ti) = 1/(tf - ti)
1/5 = 1/5