- #1

Jennifer_T

- 8

- 0

## Homework Statement

If 1.15 moles of an ideal gas has a pressure of 3.60 atm, and a volume of 81.37 L, what is the temperature of the sample in degrees Celsius?

## Homework Equations

PV=nRT

p = pressure

v = volume

n = number of moles

r = 0.08206 L atm/(mol K)

T = ?

## The Attempt at a Solution

So I did the problem by :

3.60 (81.37) = (1.15)(0.08206)(T)

I found T to be 20.9 degrees K. I converted the temperature from K to C by doing K = C + 273 so 20.9 = C + 273. So the temperate in C is -252 degrees. However, I am still getting this wrong in the online homework. Can anyone help me figure out mistake?