- #1
TylerH
- 729
- 0
First, do not give me the answer, please. This is for fun, and I want to see if I can do it.
My plan of attack:
Prove that for any m/n, where m and n are natural numbers, there is no p2/q2 < m/n, where p and q are natural numbers, such that p2/q2 is larger than all other rational squares less than m/n.
Prove that for any m/n, where m and n are natural numbers, there is no p2/q2 > m/n, where p and q are natural numbers, such that p2/q2 is smaller than all other rational squares more than m/n.
Would this prove what I intend it to, and is it possible?
My plan of attack:
Prove that for any m/n, where m and n are natural numbers, there is no p2/q2 < m/n, where p and q are natural numbers, such that p2/q2 is larger than all other rational squares less than m/n.
Prove that for any m/n, where m and n are natural numbers, there is no p2/q2 > m/n, where p and q are natural numbers, such that p2/q2 is smaller than all other rational squares more than m/n.
Would this prove what I intend it to, and is it possible?