Kummer
- 296
- 0
Prove that \sin (n^2) + \sin (n^3) is not a convergent sequence.
The sequence defined by \(\sin(n^2) + \sin(n^3)\) is proven to be non-convergent due to the oscillatory nature of the sine function. The discussion highlights that unlike simpler sequences such as \(\sin(n)\), the combination of \(\sin(n^2)\) and \(\sin(n^3)\) does not settle towards a limit as \(n\) approaches infinity. The values of \(n\) such as 3, 31, 314, 3141, and 31415 illustrate the lack of convergence in the sequence.
PREREQUISITESMathematics students, educators, and researchers interested in sequence convergence, trigonometric analysis, and real analysis concepts.
I believe that is easier. Consider n=3,31,314,3141,31415,...mathwonk said:how about just sin(n).