MHB Prove that the radius of the incircle of △ is rational

  • Thread starter Thread starter lfdahl
  • Start date Start date
  • Tags Tags
    Radius Rational
Click For Summary
The discussion centers on proving that the radius of the incircle of an isosceles triangle with rational side lengths is rational if and only if the two right triangles formed by the altitude to the base are similar to a right triangle with integer side lengths. Participants emphasize the importance of the triangle's properties and the relationship between rational dimensions and the incircle's radius. The proof hinges on the similarity of the right triangles, linking rationality to integer side lengths. The conversation includes acknowledgment of contributions and solutions presented. The overall focus is on the geometric and algebraic implications of the triangle's dimensions.
lfdahl
Gold Member
MHB
Messages
747
Reaction score
0
Let $\bigtriangleup$ be an isosceles triangle for which the length of a side and the length of the base are rational. Prove that the radius of the incircle of $\bigtriangleup $ is rational if and only if the two right triangles formed by the altitude to the base are similar to a right triangle with integer side lengths
 
Mathematics news on Phys.org
lfdahl said:
Let $\bigtriangleup$ be an isosceles triangle for which the length of a side and the length of the base are rational. Prove that the radius of the incircle of $\bigtriangleup $ is rational if and only if the two right triangles formed by the altitude to the base are similar to a right triangle with integer side lengths
my solution:
given isosceles triangle $ABC$
$h^2=x^2-\dfrac {y^2}{4}$
$h=\sqrt{\dfrac {4x^2-y^2}{4}}$
$h$ must be a perfect square
$r=\dfrac {yh}{2x+y}$
for $x,y,r$ being rational ,if x,y and h are all integers then we are done
else we can enlarge the original triangle to make them (x,y,h) all integers
so the two right triangles formed by the altitude to the base are similar to a right triangle (the bigger one) with integer side lengths
View attachment 7251
 

Attachments

  • rational radius.jpg
    rational radius.jpg
    13.1 KB · Views: 108
Last edited:
Albert said:
my solution:
given isosceles triangle $ABC$
$h^2=x^2-\dfrac {y^2}{4}$
$h=\sqrt{\dfrac {4x^2-y^2}{4}}$
$h$ must be a perfect square
$r=\dfrac {yh}{2x+y}$
for $x,y,r$ being rational ,if x,y and h are all integers then we are done
else we can enlarge the original triangle to make them (x,y,h) all integers
so the two right triangles formed by the altitude to the base are similar to a right triangle (the bigger one) with integer side lengths
Well done, Albert!Thankyou for your participation.
 

Similar threads

Replies
19
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
986
  • · Replies 59 ·
2
Replies
59
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K