Prove thatd d/dt[ r · ( v × a ) ] = r · ( v × a ̇ )

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SUMMARY

The discussion centers on proving the equation d/dt[ r · ( v × a ) ] = r · ( v × a ̇ ). Participants clarify that "a dot" refers to the time derivative of acceleration. The solution involves applying the product rule of differentiation and recognizing that the derivatives of position, velocity, and acceleration are represented as v, a, and ȧ respectively. This proof is essential for understanding the dynamics of motion in physics.

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  • Knowledge of kinematic equations relating position, velocity, and acceleration.
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Homework Statement


4. Prove that



Prove thatd d/dt[ r · ( v × a ) ] = r · ( v × a ̇ )

Homework Equations





The Attempt at a Solution


I do know how can I start. i feel confuse! please help me
 
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SAHM1500 said:

Homework Statement


4. Prove that

Prove that d/dt[ r · ( v × a ) ] = r · ( v × a ̇ )

Homework Equations



The Attempt at a Solution


I do know how can I start. i feel confuse! please help me

Hello SAHM1500. Welcome to PF !

Is that supposed to be " a dot ", i.e. the derivative of acceleration with respect to time?

Are you to prove that \displaystyle \frac{d}{dt}\left( \vec{r}\cdot\vec{v}\times\vec{a} \right)=\vec{r}\cdot\vec{v}\times\dot{\vec{a}}\ ?

If so use the product rule.

Also the following:
\displaystyle \frac{d\vec{r}}{dt}=\dot{\vec{r}}=\vec{v}

\displaystyle \frac{d\vec{v}}{dt}=\dot{\vec{v}}=\vec{a}

\displaystyle \frac{d\vec{a}}{dt}=\dot{\vec{a}}​
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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