Reading of a voltmeter having resistance R across a resistance

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Homework Help Overview

The discussion revolves around the measurement of potential difference across a resistor using a voltmeter, focusing on the relationship between the voltmeter's resistance and the resistor's resistance. The original poster presents a formula for the voltmeter reading and seeks to prove its validity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the validity of the formula V' = Ir/(R+r) and question its dimensional correctness. Some suggest the need for a circuit diagram to clarify the configuration of the resistors.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have pointed out potential errors in the original formula and assumptions regarding the current in the circuit.

Contextual Notes

There is a mention of the need to clarify whether the resistors are in series or parallel, as well as assumptions about the total current remaining constant.

Shivang kohlii
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Homework Statement



The potential difference across resistance R carrying current I is V = IR . Now if the potential difference is measured via voltmeter of resistance r , the reading on voltmeter is V' . Prove that V' = Ir/(R+r) . For what value of r does the voltmeter measure true value

Homework Equations


V=ir

The Attempt at a Solution


Initially , V = IR
FINALLY, Rnet = R × r / ( R + r)
V' = I' Rnet , where I' is telhe new current in circuit..
I don't know how to proceed
 
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Shivang kohlii said:
Prove that V' = Ir/(R+r)
That would be hard to prove since as a general statement, it's not true. You need to draw a circuit diagram and show the resistors. Are they in series? Are they in parallel? Are they even in the same part of the circuit?
 
Shivang kohlii said:
V' = Ir/(R+r) .
This looks dimensionally incorrect. The RHS has dimensions of current.
 
Looks like a typo in the solution. Missing R?

I believe you are also meant to assume the total current flowing stays the same. So I'=I.
 

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