The equation \(x^2 + y^2 = 1992\) has no solutions in natural numbers \(x\) and \(y\). This is demonstrated by analyzing the properties of numbers expressible as sums of two squares. Specifically, a number can be expressed as a sum of two squares if it has no prime factors of the form \(4k + 3\) raised to an odd power. Since 1992 includes the prime factorization \(2^3 \times 3^1 \times 83^1\), the presence of the factor \(3^1\) indicates it cannot be expressed as such. Therefore, the conclusion is that there are no natural number solutions for the equation.