Proving √2 is Irrational: A Brief Explanation

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SUMMARY

The discussion provides a definitive proof that √2 is an irrational number by assuming it can be expressed as a fraction a/b, where a and b are integers. The proof demonstrates that if both a and b were even, it leads to a contradiction, confirming that √2 cannot be expressed as a ratio of two integers. This conclusion is established through logical steps involving even and odd number definitions, ultimately validating the irrationality of √2.

PREREQUISITES
  • Understanding of rational numbers and their definitions
  • Basic knowledge of even and odd integers
  • Familiarity with algebraic manipulation and proofs
  • Concept of contradiction in mathematical proofs
NEXT STEPS
  • Study the concept of irrational numbers in depth
  • Learn about other proofs of irrationality, such as the proof for √3
  • Explore the implications of irrational numbers in real analysis
  • Investigate the historical context and significance of irrational numbers in mathematics
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Students studying mathematics, particularly those focusing on number theory and proofs, as well as educators looking for clear explanations of irrational numbers.

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Homework Statement



As the title says.

Homework Equations



Rational number: a/b for some integers a, b
Even number: 2k for some integer k
Odd number: 2j+1 for some integer j

The Attempt at a Solution



Assume √2 is a rational number. Then it can be expressed a/b for some integers a and b. Reduced to it’s lowest form, a and b cannot both be even numbers.

√2 = a/b ----> √2b=a ----> 2b2=a2 ---->a2 is even ----> a is even ----> a=2k for some integer k ----> 2b2=(2k)2 ----> b2=2k2 ----> b is even: a contradiction because both a and b cannot be even.

Hence √2 is not a rational number.
 
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