[SOLVED] Prove that the cuberoot of 2 is irrational 1. The problem statement, all variables and given/known data Prove that the cuberoot of 2 is irrational 3. The attempt at a solution Assume it is rational, and find a contradiction. 2^(1/3) = a/b, where a, b are integers, where a/b is in lowest terms, and where b != 0. 2 = a^3 / b^3 2b^3 = a^3 Aaaand stuck. Can someone give me a little push?