1. The problem statement, all variables and given/known data if n is a positive integer than √(4n-2) is irrational. 2. Relevant equations 3. The attempt at a solution √(4n-2) Assume is rational then by definition of rationality √(4n-2)=p/q for some integers p,q where q≠0 so √(2(2n-1))=p/q by factoring out the 2 as common √2 *√(2n-1) =p/q but 2n-1 is always odd so √(2n-1) is always odd now let u=√(2n-1) but √2*u cannot be factored since √2 is irrational and u is odd. so √(4n-2)≠p/q Therefore our assumption must have been wrong therefore √(4n-2) must be irrational Is this proof ok??