Proving a cubic is surjective.

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SUMMARY

The function \( f:\mathbb{R}\rightarrow\mathbb{R} \) defined by \( f(x)=x^3+2x^2-x+1 \) is not injective, as demonstrated by the counterexamples \( x=-1 \) and \( x=1 \). However, the function is surjective because it covers every element in its range, which can be shown using the Intermediate Value Theorem. The function is continuous and approaches positive and negative infinity as \( x \) tends toward large values, confirming that all real numbers are achieved as outputs.

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  • Understanding of cubic functions and their properties
  • Knowledge of injective, surjective, and bijective functions
  • Familiarity with the Intermediate Value Theorem
  • Graphing techniques for functions
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  • Learn about the properties of cubic functions and their graphs
  • Explore formal proofs of surjectivity and injectivity for polynomial functions
  • Investigate the implications of continuity on the behavior of functions
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pondzo
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Homework Statement


$$f:\mathbb{R}\rightarrow\mathbb{R}~~\text{where}~~f(x)=x^3+2x^2-x+1$$
Show if f is injective, surjective or bijective.

Homework Equations

The Attempt at a Solution



f is obviously not injective (and thus not bijective), one counter example is x=-1 and x=1.

I can see from the graph of the function that f is surjective since each element of its range is covered.
But I am not sure how i can formally write it down. If i try this;

##\text{let}~y\in\mathbb{R}## and then try to find which ##x\in\mathbb{R}## maps to y then the algebra is going to get really messy and it would take a long while. Is there a faster and easier way of showing f is injective? Can i draw the function and show that all of the co-domain is covered, or is this not formal enough?

Thank you for your time.
 
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I think that stating that the function is continuous and tends toward plus or minus infinity for large arguments should be sufficient. You might need to put a little more math and logic into it, but that is the simple argument.
 
pondzo said:

Homework Statement


$$f:\mathbb{R}\rightarrow\mathbb{R}~~\text{where}~~f(x)=x^3+2x^2-x+1$$
Show if f is injective, surjective or bijective.

Homework Equations

The Attempt at a Solution



f is obviously not injective (and thus not bijective), one counter example is x=-1 and x=1.

I can see from the graph of the function that f is surjective since each element of its range is covered.
But I am not sure how i can formally write it down. If i try this;

##\text{let}~y\in\mathbb{R}## and then try to find which ##x\in\mathbb{R}## maps to y then the algebra is going to get really messy and it would take a long while. Is there a faster and easier way of showing f is injective? Can i draw the function and show that all of the co-domain is covered, or is this not formal enough?

Thank you for your time.

Use the Intermediate Value Theorem. http://en.wikipedia.org/wiki/Intermediate_value_theorem
 

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