Proving a Equation: Solving for x in 2/(x+1) + 1/(x+2) = 1/2

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Homework Statement


Homework Equations


Show that the equation

[tex]\frac{2}{x+1}+\frac{1}{x+2} = \frac{1}{2}[/tex]

can be written as [tex]x^{2} + x - 4 = 0[/tex]





The Attempt at a Solution



mulitply the fractions on the LHS numerators by opposite denominators and multiply denominators togethter giving me:

[tex]\frac{3x + 5}{x^{2} + 3x + 2} = \frac{1}{2}[/tex]

cross multiply

[tex]x^{2} + 3x + 2 = 6x + 10[/tex]
which is rearanged to give [tex]x^{2} - 3x - 8 = 0[/tex]

which is wrong :(

Where have I gone wrong
Thx
 
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Try to guess if the statement is right... for example using the roots of the second equation in the first equation.
 
indeed, your working is correct.

the question stated is obviously incorrect ...

When you place the roots found from your equation [tex]x^{2} - 3x - 8 = 0[/tex] as Coren said back into the equation, the solution is 1/2

Steven
 
thomas49th said:
[tex]x^{2} + 3x + 2 = 6x + 10[/tex]
which is rearanged to give [tex]x^{2} - 3x - 8 = 0[/tex]

which is wrong :(

Where have I gone wrong
Thx

Nope, it's totally correct. The answer the book gives is wrong.
So, congratulations. :)