Proving a Equation: Solving for x in 2/(x+1) + 1/(x+2) = 1/2

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Homework Help Overview

The discussion revolves around proving an equation involving rational expressions, specifically solving for x in the equation 2/(x+1) + 1/(x+2) = 1/2. Participants are examining the algebraic manipulation required to transform this equation into a quadratic form.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various algebraic manipulations, including cross-multiplication and rearranging terms. There is an exploration of whether the original equation can be correctly transformed into a quadratic equation and the validity of the results obtained.

Discussion Status

Some participants express uncertainty about the correctness of their manipulations, while others suggest that the original problem statement may be flawed. There is a mix of agreement and disagreement regarding the validity of the derived equations.

Contextual Notes

Participants are working under the assumption that the original equation is correct, but there is a suggestion that the provided solution in the textbook may be incorrect. This raises questions about the accuracy of the problem statement itself.

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Homework Statement


Homework Equations


Show that the equation

[tex]\frac{2}{x+1}+\frac{1}{x+2} = \frac{1}{2}[/tex]

can be written as [tex]x^{2} + x - 4 = 0[/tex]





The Attempt at a Solution



mulitply the fractions on the LHS numerators by opposite denominators and multiply denominators togethter giving me:

[tex]\frac{3x + 5}{x^{2} + 3x + 2} = \frac{1}{2}[/tex]

cross multiply

[tex]x^{2} + 3x + 2 = 6x + 10[/tex]
which is rearanged to give [tex]x^{2} - 3x - 8 = 0[/tex]

which is wrong :(

Where have I gone wrong
Thx
 
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Try to guess if the statement is right... for example using the roots of the second equation in the first equation.
 
indeed, your working is correct.

the question stated is obviously incorrect ...

When you place the roots found from your equation [tex]x^{2} - 3x - 8 = 0[/tex] as Coren said back into the equation, the solution is 1/2

Steven
 
thomas49th said:
[tex]x^{2} + 3x + 2 = 6x + 10[/tex]
which is rearanged to give [tex]x^{2} - 3x - 8 = 0[/tex]

which is wrong :(

Where have I gone wrong
Thx

Nope, it's totally correct. The answer the book gives is wrong.
So, congratulations. :)
 

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