Proving a sum that contains complex numbers

Click For Summary
SUMMARY

The discussion centers on proving a sum involving complex numbers, specifically using the formula for the sum of a geometric series. The key formula discussed is the infinite geometric series sum, represented as \(\sum_{n=0}^\infty r^n = \frac{1}{1 - r}\), where the common ratio \(r\) is identified as \(e^{id}/2\). Participants emphasize the importance of recognizing the geometric nature of the series to facilitate the proof.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with geometric series and their summation
  • Knowledge of Euler's formula, particularly \(e^{ix} = \cos(x) + i\sin(x)\)
  • Basic calculus concepts, especially limits and convergence of series
NEXT STEPS
  • Study the derivation and applications of the geometric series sum formula
  • Explore Euler's formula in depth and its implications in complex analysis
  • Investigate convergence criteria for infinite series
  • Practice problems involving sums of complex series to solidify understanding
USEFUL FOR

Students studying complex analysis, mathematicians interested in series convergence, and educators teaching advanced calculus concepts.

homad2000
Messages
19
Reaction score
0

Homework Statement


show that:

attachment.php?attachmentid=40135&stc=1&d=1318953465.gif



I tried changing the form to the sin and cos, but I couldn't complete it..

Any hints?
 

Attachments

  • MSP12919hf2d39f2ch8fdd000012d5597g3dceh4bf.gif
    MSP12919hf2d39f2ch8fdd000012d5597g3dceh4bf.gif
    1.3 KB · Views: 624
Physics news on Phys.org
That's a geometric sequence. The sum of any geometric series is
\sum_{n=0}^\infty r^n= \frac{1}{1- r}

Here, your r is e^{id}/2.
 
aaaah!

thanks for the help!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
9
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K