Proving GL(n) Center Diagonal Matrices

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SUMMARY

The center of GL(n) consists solely of scalar matrices, specifically matrices of the form A = c*I, where c is a non-zero scalar in the field F. The discussion clarifies that while diagonal matrices can commute with certain matrices, they do not generally belong to the center unless they are scalar multiples of the identity matrix. A counterexample using 2x2 matrices demonstrates that a diagonal matrix A does not commute with a non-diagonal matrix B, reinforcing the conclusion about the center's composition.

PREREQUISITES
  • Understanding of group theory, specifically the general linear group GL(n).
  • Familiarity with matrix operations, including multiplication and inversion.
  • Knowledge of diagonal and scalar matrices.
  • Basic concepts of fields in linear algebra.
NEXT STEPS
  • Study the properties of scalar matrices in linear algebra.
  • Explore the structure of the general linear group GL(n) in more depth.
  • Learn about the implications of commutativity in matrix algebra.
  • Investigate elementary matrices and their role in matrix theory.
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Mathematicians, students of linear algebra, and anyone studying group theory or matrix theory will benefit from this discussion.

Jim Kata
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Is the center of GL(n) the set diagonal martices? It's easy to prove that ADA^-1 = D if D is diagonal, but if ABA^-1 = B is true that B is diagonal.
 
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no, the center is the set of all scalar matrices, ie, A is in the center iff A = c*I for some c in F\{0}

consider elementary matricesanother suggestion, when working on problems like this where you don't know what it is you want to prove, think simple, ie, take n = 2, and A = (1 0; 0 -1) which is diagonal, and B = (2 3; 1 1), then AB != BA, so A is not in the center but A is a diagonal matrix.
 
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