Proving $\Im (\ln(-|x|))=\pi$ for All Reals

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SUMMARY

The discussion focuses on proving that the imaginary part of the logarithm of the negative absolute value of a real number, specifically $\Im (\ln(-|x|))$, equals $\pi$ for all real numbers x. The proof involves expressing negative real numbers in polar coordinates as $re^{i\pi}$, leading to the conclusion that $\ln(-|x|) = \ln(r) + i\pi$. This confirms that the imaginary component is consistently $\pi$ across all negative values of x.

PREREQUISITES
  • Complex analysis, particularly the properties of logarithmic functions.
  • Understanding of polar coordinates and their application to complex numbers.
  • Familiarity with the concept of imaginary numbers and their representation.
  • Basic knowledge of real and complex logarithms.
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  • Study the properties of complex logarithms in detail.
  • Explore polar coordinates and their significance in complex analysis.
  • Learn about the principal branch of the logarithm and its implications.
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epkid08
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How would someone go about proving:

[tex]\Im (ln(-|x|))=\pi[/tex] for all reals, x, when the answer takes the form, a + bi.
 
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What's wrong with direct calculation?
 
epkid08 said:
How would someone go about proving:

[tex]\Im (ln(-|x|))=\pi[/tex] for all reals, x, when the answer takes the form, a + bi.

Negative real numbers can be expressed in polar coordinates as re(pi)i. Take the log and you get ln(r)+(pi)i.
 

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