Proving Inequality: a/b < (a+1)/(b+1) for b > a | Solution and Attempt

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Homework Help Overview

The discussion revolves around proving the inequality a/b < (a+1)/(b+1) under the condition that b is a positive number and a < b. Participants are exploring various methods to approach this proof.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants have attempted different methods, including clearing fractions and manipulating the inequality. Some express frustration over previous mistakes and seek clarification on valid steps in the proof.

Discussion Status

There is an ongoing exploration of different approaches to the problem. Some participants have offered suggestions, such as adding terms to both sides of the inequality, while others reflect on their previous attempts and errors.

Contextual Notes

Participants are working under the assumption that b is positive and that a is less than b, which is central to the inequality being discussed. There is acknowledgment of mistakes made in earlier attempts, which may affect the direction of the discussion.

John H
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Homework Statement



Prove that if b is a positive number, such that a < b, then
a/b<(a+1)/(b+1)

2. The attempt at a solution

I have tried a few things, attempting to prove it using the real line, and a bunch of other methods but have had no success. I Would greatly appreciate it if u can at least get me started.
 
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John H said:

Homework Statement



Prove that if b is a positive number, such that a < b, then
a/b<(a+1)/(b+1)

2. The attempt at a solution

I have tried a few things, attempting to prove it using the real line, and a bunch of other methods but have had no success. I Would greatly appreciate it if u can at least get me started.

Clear out the fractions, i.e. multiply both sides by the common denominator. You didn't try that?
 
I did before, but I made the most retarded mistake of thinking a(b+1)=b(a+1). Sorry about that. Thanx
 
a<b. You can add any number to both sides of an inequality, it stays valid. Why not trying to add ab?

ehild
 

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