Proving inf(x_n)=1 for x_{n+1}=2-\frac{1}{x_n}

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x_{n+1}=2-\frac{1}{x_n}

I need to show that inf(x_n)=1

For someone reason this is proving to be more difficult than I thought, could someone pleas help?
 
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It would be a little clearer if you defined x_0. Also your notation is a little strange - frac{1}{x} means what? I am guessing it means the fractional part, but I am not sure.
 
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hockey777 said:
[tex]x_{n+1}=2-\frac{1}{x_n}[/tex]

I need to show that inf(x_n)=1

Hi hockey777! Welcome to PF! :smile:

Hint: start by subtracting 1 from each side. :wink:

(and type [noparse][tex]before and[/tex] after your equations![/noparse] :smile:)