- #1

- 2

- 0

Thank you very much

Cosh^(-1 ) A/x=( x √(X^( 2 )+A ))/2a

my attempt=>

Cosh^(-1 ) = y

A/x = Cosh^(-1 )

A/x = Sechy

A/x= (2/(e^2 + e^-2))

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- Thread starter jamie-soc
- Start date

- #1

- 2

- 0

Thank you very much

Cosh^(-1 ) A/x=( x √(X^( 2 )+A ))/2a

my attempt=>

Cosh^(-1 ) = y

A/x = Cosh^(-1 )

A/x = Sechy

A/x= (2/(e^2 + e^-2))

- #2

- 203

- 0

http://en.wikipedia.org/wiki/List_of_logarithmic_identities

http://en.wikipedia.org/wiki/Hyperbolic_function

now you just start manipulating things, basically

- #3

- 2

- 0

Thank you , but I have looked at both of those websites.

Im having problems with the manipulation

Im having problems with the manipulation

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