Palindrom
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Hi all,
Suppose E/F and K/E are finite separable extensions. Prove: K/F is a separable extension.
I tried, but I'm stuck again. (Have you noticed I have one like this every week? And it seems I'm the only one that's even trying to submit these H.W. weekly...).
Anyway, that was my direction: Given \[<br /> \theta \in K<br /> \]<br />, I know that \[<br /> \mu _\theta \left( x \right)<br /> \]<br /> (the minimal polynomial over E) is separable. What I need to prove is that \[<br /> \hat \mu _\theta \left( x \right)<br /> \]<br />, which is the minimal polynomial over F, is separable.
I know that \[<br /> \mu '_\theta \left( x \right) \ne 0<br /> \]<br />, since \[<br /> \mu _\theta \left( x \right)<br /> \]<br />is separable and therefore \[<br /> \left( {\mu ,\mu '} \right) = 1<br /> \]<br />. I now need to prove that \[<br /> \hat \mu '_\theta \left( x \right) \ne 0<br /> \]<br />.
...
Tried all kinds of things, didn't get me far though... Any hints would be appreciated.
Suppose E/F and K/E are finite separable extensions. Prove: K/F is a separable extension.
I tried, but I'm stuck again. (Have you noticed I have one like this every week? And it seems I'm the only one that's even trying to submit these H.W. weekly...).
Anyway, that was my direction: Given \[<br /> \theta \in K<br /> \]<br />, I know that \[<br /> \mu _\theta \left( x \right)<br /> \]<br /> (the minimal polynomial over E) is separable. What I need to prove is that \[<br /> \hat \mu _\theta \left( x \right)<br /> \]<br />, which is the minimal polynomial over F, is separable.
I know that \[<br /> \mu '_\theta \left( x \right) \ne 0<br /> \]<br />, since \[<br /> \mu _\theta \left( x \right)<br /> \]<br />is separable and therefore \[<br /> \left( {\mu ,\mu '} \right) = 1<br /> \]<br />. I now need to prove that \[<br /> \hat \mu '_\theta \left( x \right) \ne 0<br /> \]<br />.
...
Tried all kinds of things, didn't get me far though... Any hints would be appreciated.