Proving Magnitude of Position Vector for Centre of Mass

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SUMMARY

The discussion focuses on proving the equation for the magnitude R of the position vector for the center of mass, expressed as M2R2 = M∑iri2 - (1/2)∑imjrij2. The key equations involved include F = MR'' and F = p', where p = ∑jrj'. The participant expresses uncertainty about their approach, particularly in manipulating the equations correctly, indicating a need for clarity in applying the principles of mechanics and vector calculus.

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  • Understanding of vector calculus and position vectors
  • Familiarity with the concepts of center of mass and mass distribution
  • Knowledge of Newton's laws of motion, specifically F = ma
  • Proficiency in using LaTeX for mathematical expressions
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  • Study the derivation of the center of mass formula in classical mechanics
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Students studying physics, particularly those focusing on mechanics, as well as educators and tutors looking to clarify concepts related to the center of mass and vector analysis.

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Homework Statement



Prove that the magnitude R of the position vector for the centre of mass from an arbitrary origin is given by the equation

M2R2 = M\summiri2 - (1/2)\summimjrij2

Homework Equations



F = MR''

F = p'

p = \summjrj'



The Attempt at a Solution



I'm not quite sure where to start with this, but this is what I've tried so far:

F = MR''

R'' = \frac{F}{M} = \frac{p&#039;}{M} = \frac{(\summ<sub>j</sub>r<sub>j</sub>&#039;)&#039;/M<br /> <br /> And that&#039;s about where I think I go wrong. Am I on the right path, or am I waaayyy off?
 
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