Proving MAX[a,b] and MIN[a,b] with Real Numbers: A Proof Question

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Homework Help Overview

The discussion revolves around proving the expressions for MAX[a, b] and MIN[a, b] using real numbers. Participants are exploring the definitions and properties of these functions, particularly focusing on the maximum function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the meaning of MAX[a, b] and MIN[a, b], with one suggesting a case-based approach to prove the maximum function using absolute values. Others express difficulty in developing a formula from the given expressions and question the validity of their reasoning.

Discussion Status

The discussion is active, with participants sharing their attempts to prove the expressions. Some have proposed splitting the absolute value into cases, while others are questioning whether their approaches are correct. There is no explicit consensus on the correctness of the proofs presented.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a note of frustration regarding the clarity of the original question and the format of the discussion.

transgalactic
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for "a" and "b" are real numbers prove that:
http://img505.imageshack.us/img505/5329/26310844lw6.gif

whats the meaning of MAX[a,b] and MIN[a,b]

how am i supposed to prove that
??
 
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Max[a, b] is "maximum of a and b" or simply the larger of the two numbers.

You are asked to prove that max[a,b] = (1/2)(a+ b+ |a- b|)

As always with absolute value problems, break it into to cases: a> b and a< b, and show that the two sides are the same in each of those cases.
 
but there are variables
even if i presume that a>b
i can't develop into a formula
i can't put it into the given expression
??
 
the only thing i can do with the given expression
is to split |a- b| into two cases
a-b>0 ->a>b
which gives me :
(1/2)(a+ b+ a- b)=a

a-b<0 a<b:
(1/2)(a+ b-a+ b)=bi got a similar resolt but it didnt came from
that in the i say "if a>b ..."
 
transgalactic said:
the only thing i can do with the given expression
is to split |a- b| into two cases
a-b>0 ->a>b
which gives me :
(1/2)(a+ b+ a- b)=a

a-b<0 a<b:
(1/2)(a+ b-a+ b)=b

That's a proof, isn't it?

What's wrong with that? :confused:

(and why didn't you type out the question, and make it easier for every one?)
 
in the first post i typed the question and added a link to the formula

regarding the question:
i did it correctly?
 

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