Proving Mean and Variance Equivalence: Step-by-Step Guide | Helpful Tips

  • Context: Undergrad 
  • Thread starter Thread starter mcguiry03
  • Start date Start date
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
mcguiry03
Messages
8
Reaction score
0
μ=αθ
σ^2=αθ^2
can someone show me how to prove that the mean and variance is equal to what is at the top... tnx a lot...:biggrin:
 
Physics news on Phys.org
Hey mcguiry03 and welcome to the forums.

You need to specify what the distribution is and what you are trying to do.

If you are starting with a distribution X and you have Y =aX and want to find the mean and variance of Y then you use the fact that E[Y] = E[aX] = aE[X] and Var[Y] = Var[aX] = a^2Var[X].

If it is something else, then you will need to specify what is going on and what you are trying to do.