Proving Non-Existence of a Limit: Solving 1/(x^2+x^3)

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Homework Help Overview

The discussion revolves around proving the non-existence of a limit for the function 1/(x²+x³) as x approaches 0. Participants are exploring the implications of limit definitions and logical negations in the context of calculus.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formal definition of a limit and its negation, questioning how to demonstrate the non-existence of a limit through quantifiers and inequalities. There is an exploration of showing that the function exceeds any positive real number for sufficiently small x.

Discussion Status

The discussion is active, with participants providing insights into logical structures and the importance of careful handling of quantifiers. Some guidance has been offered regarding the approach to take, but no consensus on a definitive method has been reached.

Contextual Notes

Participants are navigating the complexities of limit definitions and their negations, emphasizing the need for precision in logical reasoning. There are indications of potential logical traps that could mislead the proof process.

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Homework Statement

does not exist.

Prove that the limit as x approaches 0 of 1/(x2+x3)

Homework Equations





The Attempt at a Solution


I know that I have to prove that the absolute value of 1/(x2+x3) - L is greater than or equal to epsilon for some delta. What do I do next?
 
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The definition of limit says:
[tex]\exists L, \forall \epsilon > 0, \exists \delta > 0, \forall x \text{ s.t.} |x| < \delta: |f(x) - L| < \epsilon[/tex]
where L is the supposed limit.

What is the negation of this?
 
The negation would be that the absolute value of f(x)-L is greater than or equal to epsilon. But how do I prove that there exists a delta for which that is true?
 
Why don't you just show that for all positive real numbers M, |1/(x^2 + x^3)| > M if x is taken sufficiently small?
 
Yes, but you should take care with the quantifiers: the negation of
[tex] \exists L, \forall \epsilon > 0, \exists \delta > 0[/tex]
is
[tex] \forall L, \exists \epsilon > 0, \forall \delta > 0[/tex]

I was stressing this because I think it is important that you do not fall into such logical traps.

Of course, if you just want to solve the question, follow JG's advice :)
 

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