Proving p(A|B)=p(A|B'): A Step-By-Step Guide

[chopasticks]

how can i proof that >>>>>> p(A | B') = p(A | B)
well i tried but i think there is a hole in the solution T.T
if we said that
p(A|B)=p(A&B)/p(B)

p(A|B')= p(A&B')/p(b')

= p(A) - p(A&B)/1-p(B)


so0o0o how can i complete it ??

 

[arildno]

how can i proof that >>>>>> p(A | B') = p(A | B)

In general, you can't prove that.

That condition holds ONLY for independent events.

So, in a particular case, you may demonstrate whether that condition holds or not.

If it holds, A and B are independent events, if not, A and B are not independent events.

 

[chopasticks]

sorry my bad ,, i forgot to mention that A,B are independent

 

[HallsofIvy]

In that case, by definition of "independent", P(A|B)= P(A)= P(A|B').