Proving PS/PQ = TX/XR in ΔPQR with Parallel Lines

[harimakenji]

Homework Statement

At ΔPQR, a line is drawn parallel to QR, cuts PQ at S and PR at T. Line SR and QT intersect at X. Show that PS / PQ = TX / XR

Homework Equations

The Attempt at a Solution

I can not achieve that proof. The best I can get is : PS / PQ = TX / XQ. Something wrong with me or the question?

 

[Mentallic]

I also got your result. I'm placing my bets on the faulty question

 

[harimakenji]

I also got your result. I'm placing my bets on the faulty question

OK. Thanks a bunch !

 

[Mentallic]

No worries. It's nice to see you actually know how to do this question, you have no idea how many high school students (even in year 12) getting nowhere in this kind of geometry.