Proving R is an Equivalence Relation: Steps and Explanation

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SUMMARY

The discussion focuses on proving that a relation R on a set X is an equivalence relation by satisfying three specific properties: reflexivity, symmetry, and transitivity. The first property, reflexivity, is established by stating that for all a in X, (a,a) is in R. The second property, symmetry, requires that if (a,b) is in R, then (b,a) must also be in R. The third property, transitivity, asserts that if (a,b) and (b,c) are in R, then (a,c) must be in R. Participants suggest using proof by contradiction and specific examples to clarify the proof process.

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  • Familiarity with set theory concepts
  • Knowledge of proof techniques, including proof by contradiction
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  • Study the properties of equivalence relations in detail
  • Learn about proof techniques, particularly proof by contradiction
  • Explore examples of equivalence relations in set theory
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Mathematics students, educators, and anyone interested in understanding the foundations of equivalence relations and proof techniques in set theory.

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1. Let R be a relation on X that satisfies
a) for all a in X, (a,a) is in R
b) for a,b,c in X, if (a,b) and (b,c) in R, then (c,a) in R.
Show that R is an equivalence relation.




2. In order for R to be an equivalence relation, the following must be true:
1) for all a in X, (a,a) is in R
2) for a,b in X, if (a,b) is in R, then (b,a) is also in R
3) for a,b,c in X, if (a,b) and (b,c) is in R, then (a,c) is in R.




3. The first part is given by the definition of an equivalence relation. I'm stuck on proving part b. Help please!
 
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how about considering (a,b) and (b,b) for the second part?
 
lanedance said:
how about considering (a,b) and (b,b) for the second part?

Proof by contradiction, using lanedance's example.

Or consider (b,c) and (c,c).
 

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