Proving r^n > r^m through mathematical induction

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Homework Help Overview

The discussion revolves around proving the inequality r^n > r^m for a real number r in the interval (0, 1) and positive integers n and m where n < m, using mathematical induction. The participants are exploring the implications of the properties of numbers between 0 and 1 in the context of this proof.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to establish a predicate for the induction proof and express uncertainty about how to begin the proof process. There is mention of taking logarithms to assist with the inequality, and one participant shares a resource for learning about induction.

Discussion Status

The discussion is ongoing, with participants providing insights and suggestions. Some guidance has been offered regarding the inductive step, but there is no explicit consensus on the approach to take. Participants are still exploring the foundational concepts of induction.

Contextual Notes

Participants note that no calculus techniques are permitted, which may influence the methods discussed. There is also a recognition of the challenge posed by the variables involved in the proof.

tmay82
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Homework Statement



I need to prove that for any real number r, if 0 < r < 1, then for all positive integers n and m, if n < m, then r^n > r^m.


Homework Equations



No calculus techniques are permitted, only mathematical induction.

The Attempt at a Solution



I know that any fraction between 0 and 1 is going to get smaller if it is multiplied by anything positive, so this is obviously true.

I know that I first need to figure out what predicate to use, but I'm having a problem with all of the variables.

Im not looking for the answer, just a little bit of direction. Where/how do I begin? I know what to prove, I just don't know how to prove it.

Thanks for any help out there
 
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tmay82 said:

Homework Statement



I need to prove that for any real number r, if 0 < r < 1, then for all positive integers n and m, if n < m, then r^n > r^m.


Homework Equations



No calculus techniques are permitted, only mathematical induction.

The Attempt at a Solution



I know that any fraction between 0 and 1 is going to get smaller if it is multiplied by anything positive, so this is obviously true.

I know that I first need to figure out what predicate to use, but I'm having a problem with all of the variables.

Im not looking for the answer, just a little bit of direction. Where/how do I begin? I know what to prove, I just don't know how to prove it.

Thanks for any help out there

Perhaps you could take the logarithm of both sides of the inequality.
 
To be honest I don't know much about induction, but it has been something I want to learn. I wasn't going to reply here because I don't know anything about it, but I went to khan academy and found this video! Coincidence? I don't know if it's what you need, but I hope it helps.

http://www.khanacademy.org/video/proof-by-induction?playlist=Algebra
 
tmay82 said:
I know that any fraction between 0 and 1 is going to get smaller if it is multiplied by anything positive, so this is obviously true.

No, you have that the wrong way around. Anything positive is going to get smaller if multiplied by a number between 0 and 1. So that's the basis of your inductive step right there. Now you just need to write it out formally as an inductive proof.
 
Last edited:

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