Proving Summation nCk p^k q^n-k =1

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SUMMARY

The discussion focuses on proving the equation SUMMATION nCk p^k q^(n-k) = 1, where p + q = 1, using the binomial theorem. It begins with the identity (1 + x)^n = SUMMATION nCk x^k and demonstrates that substituting p and q into this identity leads to the desired result. Additionally, the general law of addition for probabilities is established, showcasing the relationship between the probabilities of unions and intersections of events.

PREREQUISITES
  • Understanding of binomial coefficients (nCk)
  • Familiarity with the binomial theorem
  • Basic knowledge of probability theory
  • Concept of event unions and intersections in probability
NEXT STEPS
  • Study the binomial theorem in detail, focusing on its applications in probability.
  • Explore advanced probability concepts, including conditional probability and independence.
  • Learn about combinatorial proofs and their role in probability theory.
  • Investigate the implications of the general law of addition in complex probability scenarios.
USEFUL FOR

Mathematicians, statisticians, and students of probability theory who are looking to deepen their understanding of binomial distributions and the foundations of probability laws.

sajee3a
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1)given that: (1+x)^n=summation nCk X^K

PROVE: SUMMATION nCk p^k q^n-k =1, where p+q=1
2) prove the general law of addition: P(E1 U E2 U...U En)=sum P(Ei)-sum P(EiEj)+sum P(EiEjEk)-...(-1)^n-1 P(E1E2...En)
 
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For 1:
1=(p+q)n=qn(1+(p/q))n=qnΣnCk(p/q)k=ΣnCkpkqn-k
 

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