Proving tan(45+x)=cot(45-x) in Degrees

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SUMMARY

The equation tan(45 + x) = cot(45 - x) is proven through trigonometric identities. The left side simplifies to cot(45 + x) using the identity tan(90 - θ) = cot(θ). The confusion arose from not factoring out a negative one from the x term, leading to an incorrect interpretation of the signs. The discussion clarifies that tan(90 + x) = cot(90 + x) is also valid, reinforcing the relationship between tangent and cotangent functions.

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Homework Statement


Prove: tan( 45 + x) =cot( 45 - x )

Note: the numbers that I am using are in deg.

Working with left side:
tan( 90 - 90 + 45 + x )
=tan(90 - 45 + x)
=tan(90 -(45+x))
=cot(45 +x)
Is my algebra correct?

If so why am I getting pos x and not a neg x?
and if this is true that is kind of weird that tan (90+x) = cot(90+x)



Homework Equations





The Attempt at a Solution

 
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Nevermind... I did not factor out a neg 1 from the x.. I know what I did wrong ..
 

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