Proving that a limit is non-existent

  • Thread starter Thread starter Mathoholic!
  • Start date Start date
  • Tags Tags
    Limit
Click For Summary
SUMMARY

The limit of the function f: D={(x,y)∈ℝ²: x+y≠0}→ℝ defined by f(x,y)=(x-y)/(x+y) as (x,y) approaches (0,0) is proven to be non-existent. Attempts to establish the limit using the ε-δ definition and polar coordinates reveal that the function oscillates and yields different values when approached along different paths, such as along the axes and the lines y=x and y=-x. This confirms the non-existence of the limit due to the function's indeterminate behavior near the origin.

PREREQUISITES
  • Understanding of limits in multivariable calculus
  • Familiarity with the ε-δ definition of limits
  • Knowledge of polar coordinates transformation
  • Ability to analyze functions for path-dependent limits
NEXT STEPS
  • Study the ε-δ definition of limits in multivariable calculus
  • Learn about path-dependent limits and their implications
  • Explore polar coordinates and their applications in limit analysis
  • Investigate examples of functions with non-existent limits
USEFUL FOR

Students and educators in calculus, particularly those focusing on multivariable limits, as well as mathematicians analyzing function behavior near singular points.

Mathoholic!
Messages
49
Reaction score
0

Homework Statement


The function is:
f: D={(x,y)\inℝ2:x+y≠0}→ℝ
(x,y)→\frac{x-y}{x+y}

They ask you to prove that the limit as (x,y)→(0,0) is non-existent.

Homework Equations





The Attempt at a Solution



My attempt at a solution was using the definition of limit: If there was a limit (L\inℝ) when (x,y)→(0,0), then \forallε>0 there would be a δ>0 for which:

||(x,y)||<δ →(implied) |f(x,y)-L|<ε

I tried guessing an ε for which there was no δ, hence proving the non-existence of the limit, but I can't seem to find it.

Another attempt at a solution was changing the expression to polar coordinates which gave me the following:

f(r,θ)=\frac{cosθ-senθ}{cosθ+senθ} \forallr>0

The limit when r→0 is always the same: f(r,θ). But since the function oscillates indeterminately, there's no limit.

Am I doing this right? I really need some good feedback on this ;)
 
Physics news on Phys.org
You have some interesting ideas. My simple version would be to note that if you approach (0,0) along the two axes, you get different limits.
 
It should be sufficient to point out that there exist points (x, y), on the line y= x, arbitrarily close to (0, 0) such that f(x, y)= 0 and, on the line y= -x, arbtririly close to (0, 0), for which f(x, y) is not defined.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
4K
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K