Two pencils of planes have a common plane

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Homework Help Overview

The problem involves determining the parameter α such that two pencils of planes, defined by lines AB and CD, share a common plane. The points A, B, C, and D are given in a three-dimensional space, and the context is rooted in projective geometry.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conditions under which a common plane exists for the two pencils of planes, including parallelism and intersection of the lines. There is mention of the need for a common solution to the equations defining the lines.

Discussion Status

The discussion is ongoing, with participants exploring various conditions for the existence of a common plane. Some have provided insights into the geometric relationships between the lines, while others are questioning the assumptions regarding the nature of the lines (e.g., whether they are skew).

Contextual Notes

There is a repeated emphasis on the equations of the lines and the geometric properties of the points involved. The original poster expresses uncertainty about the conditions necessary for the common plane, indicating a need for further clarification on the geometric implications of the given points.

beglor
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Homework Statement


Find the value of the parameter α for which the pencil of planes through the straight line AB has a common plane with the pencil of planes through the straight line CD, where A(1, 2α, α), B(3, 2, 1), C(−α, 0, α) and D(−1, 3, −3).

Homework Equations


Let Δ be a line given by two equations:
A1x+B1y+C1z+D1=0
A2x+B2y+C2z+D2=0
The collection of all planes containing a given straight line Δ is called the pencil of planes through Δ.
The plane π belongs to the pencil of planes through the line Δ if and only if there exists λ,μ∈ℝ such that the equation of the plane π is:
λ(A1x+B1y+C1z+D1)+μ(A2x+B2y+C2z+D2)=0

The Attempt at a Solution


I wrote the equations of the lines AB and CD. But I don't know the condition for a plane to be common to two pencil of planes in the same time.
 
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I took a course in projective geometry in 1959 taught by C. R. Wylie Jr. at the University of Utah. Never used it since and about the only thing I remember about it is the use of pencils of lines and pencils of planes. I always figured the terms came from projective geometry.
 
beglor said:

Homework Statement


Find the value of the parameter α for which the pencil of planes through the straight line AB has a common plane with the pencil of planes through the straight line CD, where A(1, 2α, α), B(3, 2, 1), C(−α, 0, α) and D(−1, 3, −3).

Homework Equations


Let Δ be a line given by two equations:
A1x+B1y+C1z+D1=0
A2x+B2y+C2z+D2=0
The collection of all planes containing a given straight line Δ is called the pencil of planes through Δ.
The plane π belongs to the pencil of planes through the line Δ if and only if there exists λ,μ∈ℝ such that the equation of the plane π is:
λ(A1x+B1y+C1z+D1)+μ(A2x+B2y+C2z+D2)=0

The Attempt at a Solution


I wrote the equations of the lines AB and CD. But I don't know the condition for a plane to be common to two pencil of planes in the same time.
There will be a common plane if either
  1. the pencil of planes through the line AB is parallel to the pencil of planes through CD, or
  2. the pencil of planes through the line AB intersects the pencil of planes through CD
In case 1, the vector ##\overrightarrow{AB}## will be a scalar multiple of the vector ##\overrightarrow{CD}##.
In case 2, the equations of the two lines have to have a common solution.

If the lines are skew, there can't be a common plane.

I think I've covered all the possibilities...
 
beglor said:

Homework Statement


Find the value of the parameter α for which the pencil of planes through the straight line AB has a common plane with the pencil of planes through the straight line CD, where A(1, 2α, α), B(3, 2, 1), C(−α, 0, α) and D(−1, 3, −3).

Homework Equations


Let Δ be a line given by two equations:
A1x+B1y+C1z+D1=0
A2x+B2y+C2z+D2=0
The collection of all planes containing a given straight line Δ is called the pencil of planes through Δ.
The plane π belongs to the pencil of planes through the line Δ if and only if there exists λ,μ∈ℝ such that the equation of the plane π is:
λ(A1x+B1y+C1z+D1)+μ(A2x+B2y+C2z+D2)=0

The Attempt at a Solution


I wrote the equations of the lines AB and CD. But I don't know the condition for a plane to be common to two pencil of planes in the same time.

You want to find a plane that contains both lines AB and CD, so contains the four points A, B, C and D. It is a standard exercise to find the plane containing the three points A, B and C; then you can fix ##\alpha## by requiring that the fourth point, D, must also lie in the same plane.
 

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