MHB Proving that solutions of a equation are irrational

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how to prove that solutions of the following equation are irrational

x^3 + x + 1 = 0
 
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ranga519 said:
how to prove that solutions of the following equation are irrational

x^3 + x + 1 = 0

Hi Ranga,

I do not know what your course material says, but we have the Rational Root Theorem to work with.
Since neither $x=-1$ nor $x=1$ is a solution, that implies that there is no rational root.
 
You can prove it by contradiction. It is essentially the same proof as the proof of $\sqrt 2$ being irrational.

Assume x is rational, then x can be given as $x=p/q$ where p and q have no common primefactors. The equation becomes $$\frac{p^3}{q^3}+\frac{p}{q}+1=0 \Leftrightarrow p^3=-q^2(p+q)$$
Can you se the contradiction now?
 
I posted this question on math-stackexchange but apparently I asked something stupid and I was downvoted. I still don't have an answer to my question so I hope someone in here can help me or at least explain me why I am asking something stupid. I started studying Complex Analysis and came upon the following theorem which is a direct consequence of the Cauchy-Goursat theorem: Let ##f:D\to\mathbb{C}## be an anlytic function over a simply connected region ##D##. If ##a## and ##z## are part of...

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