Proving that the parity of a permutation is well defined.

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SUMMARY

The discussion centers on the proof of the well-defined nature of the parity of a permutation in the symmetric group Sn. Participants critique a common proof method that involves demonstrating the even parity of the identity permutation and manipulating transpositions through defined "moves." The conversation highlights the perceived clumsiness of this proof and seeks alternative, more concise proofs. Additionally, the definition of the sign of a permutation is provided, emphasizing its relationship to the number of inversions.

PREREQUISITES
  • Understanding of symmetric groups, specifically Sn.
  • Familiarity with the concept of transpositions in permutations.
  • Knowledge of the definition and properties of the sign of a permutation.
  • Basic principles of mathematical induction.
NEXT STEPS
  • Research alternative proofs for the well-defined nature of permutation parity.
  • Study the equivalence of different definitions of the sign of a permutation.
  • Explore elegant proofs of permutation parity as discussed on Wikipedia.
  • Investigate the implications of the number of inversions in permutations.
USEFUL FOR

Mathematicians, algebra students, and anyone interested in group theory and the properties of permutations will benefit from this discussion.

espen180
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All the proofs I have seen for this theorem uses the same argument: First prove that the identity permutation has even parity. Then let a be (one of) the first elements to appear in a transposition representation of a permutation in Sn. Then identify all the other transpositions in the representation that also feature a and play with the order and such using two defined "moves" that "move" a in a specified direction. Since only a finite number of transpositions feature a, we can eventually cancel two, leaving us with a representation of 2 less transpositions. The theorem follows by an induction argument.

I think this is a somewhat ugly and clumsy proof, probably my least favorite in my algebra book. Does anyone know if there exists another, shorter proof, which does not invoke this "moving" argument?
 
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espen180 said:
All the proofs I have seen for this theorem uses the same argument: First prove that the identity permutation has even parity. Then let a be (one of) the first elements to appear in a transposition representation of a permutation in Sn. Then identify all the other transpositions in the representation that also feature a and play with the order and such using two defined "moves" that "move" a in a specified direction. Since only a finite number of transpositions feature a, we can eventually cancel two, leaving us with a representation of 2 less transpositions. The theorem follows by an induction argument.

I think this is a somewhat ugly and clumsy proof, probably my least favorite in my algebra book. Does anyone know if there exists another, shorter proof, which does not invoke this "moving" argument?


If \sigma\in S_n is a permutation, the DEFINITION of the sign of \sigma is Syg(\sigma):=\prod_{1\leq i< j\leq n}\frac{i-j}{\sigma(i)-\sigma(j)} .

I can't see how the above can't be well defined: the above is 1 if the number of inversions in the order of each pair (i,j) in the image of \sigma is even,

and -1 otherwise. What is there to proof?

DonAntonio
 
Assuming that is given as the definition of sign, which it isn't always

Wikipedia discusses the equivalence of the two definitions and gives several elegant proofs in my opinion (which equivalently can be thought of as proving that the sign is well defined in the number of transpositions sense)

http://en.wikipedia.org/wiki/Parity_of_a_permutation
 
Office_Shredder said:
Assuming that is given as the definition of sign, which it isn't always

Wikipedia discusses the equivalence of the two definitions and gives several elegant proofs in my opinion (which equivalently can be thought of as proving that the sign is well defined in the number of transpositions sense)

http://en.wikipedia.org/wiki/Parity_of_a_permutation



Well, then it may be what you wrote in the last lines: take one definition and prove that another one is equivalent to it.

This though wasn't what the OP wanted, at least from what I can understand in his question.

DonAntonio
 

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