Proving the Equality of Newton Binomial Coefficient Using the Summation Method

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Homework Help Overview

The discussion revolves around proving the equality of two expressions involving the binomial coefficient, specifically showing that the summation of binomial coefficients from k=0 to n equals 2^n. The subject area is combinatorics and the binomial theorem.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to sum the binomial coefficients and relate them to 2^n. Some participants suggest using the binomial theorem, while others question the definitions and variables involved in the theorem.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the binomial theorem and its application. There is a lack of consensus on the definitions and the approach to take, but some guidance has been offered regarding the use of the binomial theorem.

Contextual Notes

Participants note that there may be confusion regarding the variables used in the binomial theorem, and there is an expectation for the original poster to engage with the material independently.

Abukadu
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Homework Statement



http://img82.imageshack.us/img82/8125/78492134fy0.th.jpg http://g.imageshack.us/thpix.php

I need to prove that the left part is equal to the right. I'm not sure how to approach the question.
I know that (n over k)=n! : k!(n-k)! but how do I sum all the number from k=0 to k=n and show that that equals to 2^n ?
 
Last edited by a moderator:
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Abukadu said:

Homework Statement



http://img82.imageshack.us/img82/8125/78492134fy0.th.jpg http://g.imageshack.us/thpix.php

I need to prove that the left part is equal to the right. I'm not sure how to approach the question.
I know that (n over k)=n! : k!(n-k)! but how do I sum all the number from k=0 to k=n and show that that equals to 2^n ?

use the binomial theorem and let x=y=1

marlon
 
Last edited by a moderator:
hi marlon
what do you mean by x=y=1?
what is my x and y? the binomial theorem has r and y
 
What IS the binomial theorem?
 
We were kind of hoping that Abukadu would look it up himself! And, no, y is NOT equal to 0. If it were you would just have xn= xn
 

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